Link available in browse screen?

adam5sbass · April 4, 2021, 4:27am

Hello team,

I’m looking for information on how to make a field on the browse screen available as a link, so the user can click on it directly and not have to open the entry and copy the link to go to it. I haven’t found a way to do this in searching, but of course my search terms could be poor.

Thanks!,
Adam

n.shatalova · April 5, 2021, 11:35am

Hi.

Can you explain in detail what you want to get as a result?

For example, you have a field link in your entity with text “https://google.com” and you want to click on this link in the browser table and open Google start page.

Regards,
Nadezhda.

adam5sbass · April 5, 2021, 12:48pm

Hello Nadezhda,

Yes, that’s pretty much the expected functionality.

Thanks,
Adam

n.shatalova · April 5, 2021, 1:04pm

You should create component Link for each link in your table.

Here is an example how it could be implemented with adding extra column:

    @Inject
    private GroupTable<NewEntity> newEntitiesTable;
    @Inject
    private UiComponents uiComponents;

    @Subscribe
    public void onBeforeShow(BeforeShowEvent event) {
        newEntitiesTable.addGeneratedColumn("buttonColumn", newEntity ->{
            Link link = uiComponents.create(Link.class);
            link.setUrl(newEntity.getUrl());
            link.setCaption(newEntity.getCaption());
            return link;
        });
    }

As a result in runtime it looks like this:

Pay attention to your URL, it should be an absolute.